(x^2+y^2)-(4x^2+3y^2)=

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Solution for (x^2+y^2)-(4x^2+3y^2)= equation:


Simplifying
(x2 + y2) + -1(4x2 + 3y2) = 0

Remove parenthesis around (x2 + y2)
x2 + y2 + -1(4x2 + 3y2) = 0
x2 + y2 + (4x2 * -1 + 3y2 * -1) = 0
x2 + y2 + (-4x2 + -3y2) = 0

Reorder the terms:
x2 + -4x2 + y2 + -3y2 = 0

Combine like terms: x2 + -4x2 = -3x2
-3x2 + y2 + -3y2 = 0

Combine like terms: y2 + -3y2 = -2y2
-3x2 + -2y2 = 0

Solving
-3x2 + -2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2y2' to each side of the equation.
-3x2 + -2y2 + 2y2 = 0 + 2y2

Combine like terms: -2y2 + 2y2 = 0
-3x2 + 0 = 0 + 2y2
-3x2 = 0 + 2y2
Remove the zero:
-3x2 = 2y2

Divide each side by '-3'.
x2 = -0.6666666667y2

Simplifying
x2 = -0.6666666667y2

Combine like terms: -0.6666666667y2 + 0.6666666667y2 = 0.0000000000
x2 + 0.6666666667y2 = 0.0000000000

The solution to this equation could not be determined.

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